[SEL] Need Spring Help

[Gary Epps]

Thanks Curt for clearing that up for me.  This email goes in the keeper 
file.

Gary
----- Original Message ----- 
From: "Curt" <curt at imc-group.com>
To: "The SEL email discussion list" <sel at lists.stationary-engine.com>
Sent: Friday, October 20, 2006 11:33 AM
Subject: Re: [SEL] Need Spring Help


> Gary,
> In the example to Paul that is the amount of deflection measured at a 
> given weight on the scale. That's why you really need an assistant. One to 
> push on the spring and read off the weight, while you are reading the 
> compressed spring height with a machinist scale. .
>
> For the same spring you might have made the following measurements.
>
> 50# at 3/4" (.75") of deflection.
> 25# at 3/8" (.375") of deflection.
> 70# at 1" of deflection.
>
> Figure the krate for each measurment as:
>
> 50# / .75" = 67 #/inch
> 25# / .375" = 67 #/inch
> 70# / 1" = 70 #/inch
>
> By taking several measurements at various compression differences, you can 
> both check your work and obtain an average k-rate for your spring. You go 
> to the catalog and look for springs in the 65 to 75 #/in k-rate.
>
> Curt Holland
> Gastonia, NC
>
>
>
> Gary Epps wrote:
>
>> Curt, is the .75 divisor simply a part of the formula or does it 
>> represent a factor that we might recognize?
>> Gary
>>
>>> will calculate the k-rate, by taking the 50# and dividing it by 0.75" .
>>
>>
>>
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>
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