[SEL] horsepower formula

[Jim O'Hagan]

Hi Guys,
   If I read the formula correctly, The area of a cyl is NOT 3.14x "D"[bore"
]but 3.14  x R SQD.[RXR] Plug in the #'s and see if you come closer to the
advertised HP.   Cya,   Jimmy O'Hagan

Jim O'Hagan
-----Original Message-----
From: sel-bounces at lists.stationary-engine.com
[mailto:sel-bounces at lists.stationary-engine.com] On Behalf Of Dave Rotigel
Sent: Tuesday, September 14, 2004 5:50 PM
To: The SEL email discussion list
Subject: Re: [SEL] horsepower formula

From: "Rob Skinner" <rskinner at rustyiron.com>
> > Does anyone have the formula for figuring out HP handy?
> http://engines.rustyiron.com/rig/horsepower.html

Hi Rob,
    Thanks for this formula! Five years ago I bought what I thought was a 16
HP Galloway. (See:
http://www.oldengine.org/members/rotigel/trailer/16_GallowayTrailer/index.ht
ml)
Even Ted Brookover thought it was a 16 HP (see the last several pictures in
the above.)
    Now however (using your formula) I find that the engine that George Best
located for me 5 years ago is a 6.9 HP engine. I'll never be able to show
the engine again and think that I may just sell it. Do you have any idea
what a 6.9 (likely only a 6) HP Galloway is worth?
    I arrived at the 6.9 HP by using your formula--8.25 (bore) X 3.14=
25.905. 25.905 X 16 (the stroke)= 414.48. 414.48 X 225 (RPM)= 93,258. 93,258
divided by 13,400= 6.959552238 HP.
    I'm so ashamed! I've been telling people for the past 4 years that the
engine was a 16 HP. Now I know that I'm wrong. I intend to put a FOR SALE
sign on the engine at the show this weekend and the first person that wants
a 6 HP Galloway can have it. I'll be looking for a 16 HP Galloway as soon as
I can unload this DOG!
    Dave
PS, A package should arrive for you and Kelley tomorrow!

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